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Author Topic: How many do you need?  (Read 25046 times)

MDV

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Re: How many do you need?
« Reply #75 on: April 17, 2009, 01:33:37 PM »
I own 1 guitar, my better half owns the rest :)

You have a woman that has more guitars than you?

Where did you find her?

me want

(Best I ever got in that regard was a girlfriend that wanted to learn and had a beat up epiphone she never played).

dheim

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Re: How many do you need?
« Reply #76 on: April 17, 2009, 01:54:05 PM »
I own 1 guitar, my better half owns the rest :)

You have a woman that has more guitars than you?

Where did you find her?

me want

(Best I ever got in that regard was a girlfriend that wanted to learn and had a beat up epiphone she never played).

the best i ever had was a girl whose brother had a squier strato and asked me some playing advice...
Mule, MQ, Stockholm, CS, RY, MM, PK, ANB, CNB, AWP, CWP, PiG90...

too many? ;)

dheim

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Re: How many do you need?
« Reply #77 on: April 17, 2009, 02:00:07 PM »
going back to topic i'm starting to neglect the exact number of electric guitars i own, but i think i've reached 11. or 12, maybe.

in strict technical tems i NEED one of them.
i know, one is more vintage oriented, another has got p90s, another has got a trem i don't use, another has coil split... but i know people who play everything, and much, much better than me with one. single. guitar.

but it's like girls... you actually NEED one, but who wouldn't like an harem? ;)

the best thing about having a girlfriend that doesn't play guitar is that she'll never read these words...
Mule, MQ, Stockholm, CS, RY, MM, PK, ANB, CNB, AWP, CWP, PiG90...

too many? ;)

CaptainDesslock

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Re: How many do you need?
« Reply #78 on: April 17, 2009, 02:15:27 PM »
B) A collection I always wanted X,Y,Z and I am going to have them

I NEED-

Red sparkly Mattocaster (almost done, yay!)
Chrome Mattocaster
Olympic White Strat
Gold Tele Thinline
CreamVintage-esque tele
and a yet to be decided blue something

with the exception of the gold thinline (its a rather charming squier) all will be future Legra's so it will be awhile (Red Sparkle will be done this year, and the vintage tele hopefully next year)


E) I have to have a range of colours and styles to match my shoes and shirt I can't possibly be seen with a guitar that clashes

lol, sadly a red mattocaster to match red pants and a chrome one to match black pants
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dheim

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Re: How many do you need?
« Reply #79 on: April 17, 2009, 02:19:30 PM »
Theres a topic?

X-ray...cool. Been a while since I did that, and it was only crystalography. Probably much more straighforward.

uhm... cristallography is done with x-rays, so i think it's the same thing...
Mule, MQ, Stockholm, CS, RY, MM, PK, ANB, CNB, AWP, CWP, PiG90...

too many? ;)

MDV

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Re: How many do you need?
« Reply #80 on: April 17, 2009, 02:23:06 PM »
Theres a topic?

X-ray...cool. Been a while since I did that, and it was only crystalography. Probably much more straighforward.

uhm... cristallography is done with x-rays, so i think it's the same thing...

yeah, I know its the same method - its that the x-ray diffraction shows clear repeating geometries in crystalography given different lattice shapes, and its pretty easy to interpret.

Organic molecules would be harder.

dheim

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Re: How many do you need?
« Reply #81 on: April 17, 2009, 02:27:46 PM »
Theres a topic?

X-ray...cool. Been a while since I did that, and it was only crystalography. Probably much more straighforward.

uhm... cristallography is done with x-rays, so i think it's the same thing...

yeah, I know its the same method - its that the x-ray diffraction shows clear repeating geometries in crystalography given different lattice shapes, and its pretty easy to interpret.

Organic molecules would be harder.

i bet so. and very fascinating...
but i'm just a surgeon, when i got frustrated by a thing i can't understand i OPEN IT.
Mule, MQ, Stockholm, CS, RY, MM, PK, ANB, CNB, AWP, CWP, PiG90...

too many? ;)

Roobubba

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Re: How many do you need?
« Reply #82 on: April 17, 2009, 03:56:26 PM »
Theres a topic?

X-ray...cool. Been a while since I did that, and it was only crystalography. Probably much more straighforward.

uhm... cristallography is done with x-rays, so i think it's the same thing...

yeah, I know its the same method - its that the x-ray diffraction shows clear repeating geometries in crystalography given different lattice shapes, and its pretty easy to interpret.

Organic molecules would be harder.

Actually, organic small-molecule crystallography is considerably easier. Due to the nature of the beast, those guys tend to grow crystals on the scale of sugar granules in granulated sugar, and those crystals tend to diffract very strongly, giving high resolution (usually considerably better than 1 Angstrom). In protein crystallography we tend to deal with crystals in the order of 10-50 micrometres in each dimension, which in general you have to 'fish' by hand from a drop of anywhere from 4 microlitres to 100 nanolitres with a small nylon loop, mounted on the end of a metal pin. Once you have the crystal in the loop (probably having first transferred it using the same loop method to another drop which contains a cryoprotectant solution to stop ice formation in the next step), you then typically plunge freeze the crystal in liquid nitrogen, or place it in a cryostream of nitrogen gas at 100K.
The next tricky thing is the sheer number of approximations required in protein crystallography. Assuming that you have a protein crystal which diffracts X-rays, and that those diffracted X-rays are reliably measurable to a usable resolution (we tend to like 2.5 Angstroms or better for the ligand-bound structural work I do), you then integrate your whole dataset (something like 50-200 images, each around 10-20 megabytes), and solve the structure (increasingly by using an existing structure that's similar to generate an approximate set of phases (information which you cannot gain from the diffraction pattern), but also by locating heavy (or anomalously dispersing) atoms in the unit cell (exactly like small molecule crystallography)).
Having solved the structure, you then need to refine it. You'll typically have 1000-4000 heavy (non-H) atoms in the single protein molecule, so the positions, temperature factors and occupancies of these atoms need to be refined - the product of which is your 'X-ray crystal structure', which is in fact a model based on the data you collected.
Because the data you collected probably comprises something like 10,000 to 30,000 unique data points, and you have, say 2000 atoms, each with x, y and z coordinates (that's 6000 parameters), and some contribution from temperature factor estimation, and probably a further 20-400 water molecules (depending on resolution), each of which has another 4 parameters associated (assuming an occupancy of 1 for each), your observation to parameter ratio gets quite small (approaching 1 is bad!).
Protein crystals which diffract more strongly and give measurable diffracted X-ray spots at around, say, 1.5 Angstrom resolution tend to give much more reliable models, but even these require a LOT of approximations. We are helped enormously by the requirements of chemical bonding, of course: peptide bonds tend to be planar, due to the lone pair of electrons on amide nitrogen atoms being partially delocalised with the formal pi orbitals of the adjacent carbonyl group; bond angles and bond distances tend to be pretty well defined; there are fairly few rotamers (conformations of amino acid side-chains) which are much more likely than others (again, due to chemical bonding restraints); certain values of phi and psi (and omega) - the angles within and between adjacent peptide bonds - are much more likely than others, and define the secondary structural elements, such as alpha helices, beta sheets, strict beta turns, eta helices and so on. All of these restraints, which we know largely from small molecule crystallography, help to reduce the apparent observation to parameter ratio by restricting the values that some of our parameters can take (eg by limiting in space (x,y and z) where a certain atom can be based on its bonding pattern with neighbouring atoms).


Oops, looks like I got a bit carried away and re-derailed this topic again...

Roo

Philly Q

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Re: How many do you need?
« Reply #83 on: April 17, 2009, 04:01:02 PM »
[fingers in ears] 
LaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLa not listening
LaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLaLa not listening 
[/fingers in ears]
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BKPs I Had:  RY+Abraxas, Crawlers, BD+SM

dave_mc

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Re: How many do you need?
« Reply #84 on: April 17, 2009, 04:33:17 PM »
You can have as many as you want, for whatever reason you want. Case closed. NEXT!

+1

I have 8 at the moment... personally there are a few more which i "need" in order to get certain classic tones (e.g. I don't have a tele yet), so I'm guessing I won't know whether or not I have a disease until I have all those classics covered... that's my excuse anyway :lol:

MDV

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Re: How many do you need?
« Reply #85 on: April 17, 2009, 04:51:49 PM »
Theres a topic?

X-ray...cool. Been a while since I did that, and it was only crystalography. Probably much more straighforward.

uhm... cristallography is done with x-rays, so i think it's the same thing...

yeah, I know its the same method - its that the x-ray diffraction shows clear repeating geometries in crystalography given different lattice shapes, and its pretty easy to interpret.

Organic molecules would be harder.

Actually, organic small-molecule crystallography is considerably easier. Due to the nature of the beast, those guys tend to grow crystals on the scale of sugar granules in granulated sugar, and those crystals tend to diffract very strongly, giving high resolution (usually considerably better than 1 Angstrom). In protein crystallography we tend to deal with crystals in the order of 10-50 micrometres in each dimension, which in general you have to 'fish' by hand from a drop of anywhere from 4 microlitres to 100 nanolitres with a small nylon loop, mounted on the end of a metal pin. Once you have the crystal in the loop (probably having first transferred it using the same loop method to another drop which contains a cryoprotectant solution to stop ice formation in the next step), you then typically plunge freeze the crystal in liquid nitrogen, or place it in a cryostream of nitrogen gas at 100K.
The next tricky thing is the sheer number of approximations required in protein crystallography. Assuming that you have a protein crystal which diffracts X-rays, and that those diffracted X-rays are reliably measurable to a usable resolution (we tend to like 2.5 Angstroms or better for the ligand-bound structural work I do), you then integrate your whole dataset (something like 50-200 images, each around 10-20 megabytes), and solve the structure (increasingly by using an existing structure that's similar to generate an approximate set of phases (information which you cannot gain from the diffraction pattern), but also by locating heavy (or anomalously dispersing) atoms in the unit cell (exactly like small molecule crystallography)).
Having solved the structure, you then need to refine it. You'll typically have 1000-4000 heavy (non-H) atoms in the single protein molecule, so the positions, temperature factors and occupancies of these atoms need to be refined - the product of which is your 'X-ray crystal structure', which is in fact a model based on the data you collected.
Because the data you collected probably comprises something like 10,000 to 30,000 unique data points, and you have, say 2000 atoms, each with x, y and z coordinates (that's 6000 parameters), and some contribution from temperature factor estimation, and probably a further 20-400 water molecules (depending on resolution), each of which has another 4 parameters associated (assuming an occupancy of 1 for each), your observation to parameter ratio gets quite small (approaching 1 is bad!).
Protein crystals which diffract more strongly and give measurable diffracted X-ray spots at around, say, 1.5 Angstrom resolution tend to give much more reliable models, but even these require a LOT of approximations. We are helped enormously by the requirements of chemical bonding, of course: peptide bonds tend to be planar, due to the lone pair of electrons on amide nitrogen atoms being partially delocalised with the formal pi orbitals of the adjacent carbonyl group; bond angles and bond distances tend to be pretty well defined; there are fairly few rotamers (conformations of amino acid side-chains) which are much more likely than others (again, due to chemical bonding restraints); certain values of phi and psi (and omega) - the angles within and between adjacent peptide bonds - are much more likely than others, and define the secondary structural elements, such as alpha helices, beta sheets, strict beta turns, eta helices and so on. All of these restraints, which we know largely from small molecule crystallography, help to reduce the apparent observation to parameter ratio by restricting the values that some of our parameters can take (eg by limiting in space (x,y and z) where a certain atom can be based on its bonding pattern with neighbouring atoms).


Oops, looks like I got a bit carried away and re-derailed this topic again...

Roo

How do you get the baseline models to extrapolate from? It strikes me that a computational technique like DPD, or straight up atomistic modelling would be usefull to create some starting points? 1.5 angstroms is a tad clumsy - can you get atomistic resloution reliably out of that? Seems that its very much the broad strokes of the molecular structure, how do you fill in the fine detail? The statistical interpolation at the end worries me...

dheim

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Re: How many do you need?
« Reply #86 on: April 17, 2009, 04:58:12 PM »
Theres a topic?

X-ray...cool. Been a while since I did that, and it was only crystalography. Probably much more straighforward.

uhm... cristallography is done with x-rays, so i think it's the same thing...

yeah, I know its the same method - its that the x-ray diffraction shows clear repeating geometries in crystalography given different lattice shapes, and its pretty easy to interpret.

Organic molecules would be harder.

Actually, organic small-molecule crystallography is considerably easier. Due to the nature of the beast, those guys tend to grow crystals on the scale of sugar granules in granulated sugar, and those crystals tend to diffract very strongly, giving high resolution (usually considerably better than 1 Angstrom). In protein crystallography we tend to deal with crystals in the order of 10-50 micrometres in each dimension, which in general you have to 'fish' by hand from a drop of anywhere from 4 microlitres to 100 nanolitres with a small nylon loop, mounted on the end of a metal pin. Once you have the crystal in the loop (probably having first transferred it using the same loop method to another drop which contains a cryoprotectant solution to stop ice formation in the next step), you then typically plunge freeze the crystal in liquid nitrogen, or place it in a cryostream of nitrogen gas at 100K.
The next tricky thing is the sheer number of approximations required in protein crystallography. Assuming that you have a protein crystal which diffracts X-rays, and that those diffracted X-rays are reliably measurable to a usable resolution (we tend to like 2.5 Angstroms or better for the ligand-bound structural work I do), you then integrate your whole dataset (something like 50-200 images, each around 10-20 megabytes), and solve the structure (increasingly by using an existing structure that's similar to generate an approximate set of phases (information which you cannot gain from the diffraction pattern), but also by locating heavy (or anomalously dispersing) atoms in the unit cell (exactly like small molecule crystallography)).
Having solved the structure, you then need to refine it. You'll typically have 1000-4000 heavy (non-H) atoms in the single protein molecule, so the positions, temperature factors and occupancies of these atoms need to be refined - the product of which is your 'X-ray crystal structure', which is in fact a model based on the data you collected.
Because the data you collected probably comprises something like 10,000 to 30,000 unique data points, and you have, say 2000 atoms, each with x, y and z coordinates (that's 6000 parameters), and some contribution from temperature factor estimation, and probably a further 20-400 water molecules (depending on resolution), each of which has another 4 parameters associated (assuming an occupancy of 1 for each), your observation to parameter ratio gets quite small (approaching 1 is bad!).
Protein crystals which diffract more strongly and give measurable diffracted X-ray spots at around, say, 1.5 Angstrom resolution tend to give much more reliable models, but even these require a LOT of approximations. We are helped enormously by the requirements of chemical bonding, of course: peptide bonds tend to be planar, due to the lone pair of electrons on amide nitrogen atoms being partially delocalised with the formal pi orbitals of the adjacent carbonyl group; bond angles and bond distances tend to be pretty well defined; there are fairly few rotamers (conformations of amino acid side-chains) which are much more likely than others (again, due to chemical bonding restraints); certain values of phi and psi (and omega) - the angles within and between adjacent peptide bonds - are much more likely than others, and define the secondary structural elements, such as alpha helices, beta sheets, strict beta turns, eta helices and so on. All of these restraints, which we know largely from small molecule crystallography, help to reduce the apparent observation to parameter ratio by restricting the values that some of our parameters can take (eg by limiting in space (x,y and z) where a certain atom can be based on its bonding pattern with neighbouring atoms).


Oops, looks like I got a bit carried away and re-derailed this topic again...

Roo

How do you get the baseline models to extrapolate from? It strikes me that a computational technique like DPD, or straight up atomistic modelling would be usefull to create some starting points? 1.5 angstroms is a tad clumsy - can you get atomistic resloution reliably out of that? Seems that its very much the broad strokes of the molecular structure, how do you fill in the fine detail? The statistical interpolation at the end worries me...

i'm beginning to feel the urge to OPEN UP someone...  :twisted:
Mule, MQ, Stockholm, CS, RY, MM, PK, ANB, CNB, AWP, CWP, PiG90...

too many? ;)

HTH AMPS

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Re: How many do you need?
« Reply #87 on: April 17, 2009, 05:03:41 PM »
My collection comprises...

* a Les Paul standard (the only guitar I ever wanted BADLY and will always own)
* a 72 Tele Custom RI (gotta have a Tele in the collection, it's a tone that ONLY a Tele can do).
* an Explorer with EMGs for metal (thinner neck and flatter board makes it play MUCH faster than the LP)

With the guitars above I can get pretty much all the tones I want for gigging.

My 'wants' are as follows...

* Les Paul Junior in tobacco sunburst (had one recently but was skint and sold it, was GORGEOUS too with that BKP91)
* '60s SG Junior in white (P90s SCREAMED in this era of Gibsons)
* Gibson 335 in cherry-red with a Bigsby
* Gretsch White Falcon
* Rickenbacker 360 in jetglo (black) like Peter Buck's one
* '58 Gibson Flying Vee RI (Korina)
* Ran 'Dean Vee' replica as a metal-monster with a Khaler and white binding around the whole body fitted with Painkillers  :twisted:

GuiTony

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Re: How many do you need?
« Reply #88 on: April 17, 2009, 05:20:21 PM »
I have "20-something" guitars.  Depending on which ones I include in the count, and which ones I forget to include.

Late last year, I picked up one of them which I hadn't played for ages, and realised how good it felt and sounded.  I then asked myself why I'd neglected it for so long ... and realised that it was because I'd been playing other guitars instead.  The "others" might have been newer, or easier to get to, or some other dumb reason, but they weren't as good.

So I decided that the New Year would bring a clearout, and I'd get down to a core of "great" (to me) guitars.  I even drew up a hit list and ranked them.

I've managed to sell 2.  I took one apart, but then re-built it.  But I'll take that one apart again, 'cos it's still cr4p.  SO that's -3 for the year.  There are a couple of others (1 Brian Moore, 1 Nathan Sheppard, just in case anyone's interested!) that I'd sell if I get sensible offers, but I'm not giving them away and there doesn't seem to be a lot of spare cash around atm.

So that could be -5 ... except that I've bought 2 new ones (both Kawais, which completed my mini-collection).  There'll be another new arrival when Wez finishes it.  And I've got another one half-built in my workshop.  So the clearout hasn't been hugely successful.   :P

The reason ... my Kawai collection has taken me at least the last 5 years to track down - after buying my original one about 30 years ago.  The male species are genetically programmed to collect stuff (actually, that's a serious statement) and I figure that at least I'm collecting something useful, rather than old stamps, beermats, bird eggs, et al.  And the Wez build is because I promised myself one when I saw a couple of his earlier builds, and you really shouldn't break promises.  Specially not promises to yourself.
Kawai Guitars are HERE ...www.kawaiguitars.com

Roobubba

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Re: How many do you need?
« Reply #89 on: April 17, 2009, 05:42:02 PM »
Theres a topic?

X-ray...cool. Been a while since I did that, and it was only crystalography. Probably much more straighforward.

uhm... cristallography is done with x-rays, so i think it's the same thing...

yeah, I know its the same method - its that the x-ray diffraction shows clear repeating geometries in crystalography given different lattice shapes, and its pretty easy to interpret.

Organic molecules would be harder.

Actually, organic small-molecule crystallography is considerably easier. Due to the nature of the beast, those guys tend to grow crystals on the scale of sugar granules in granulated sugar, and those crystals tend to diffract very strongly, giving high resolution (usually considerably better than 1 Angstrom). In protein crystallography we tend to deal with crystals in the order of 10-50 micrometres in each dimension, which in general you have to 'fish' by hand from a drop of anywhere from 4 microlitres to 100 nanolitres with a small nylon loop, mounted on the end of a metal pin. Once you have the crystal in the loop (probably having first transferred it using the same loop method to another drop which contains a cryoprotectant solution to stop ice formation in the next step), you then typically plunge freeze the crystal in liquid nitrogen, or place it in a cryostream of nitrogen gas at 100K.
The next tricky thing is the sheer number of approximations required in protein crystallography. Assuming that you have a protein crystal which diffracts X-rays, and that those diffracted X-rays are reliably measurable to a usable resolution (we tend to like 2.5 Angstroms or better for the ligand-bound structural work I do), you then integrate your whole dataset (something like 50-200 images, each around 10-20 megabytes), and solve the structure (increasingly by using an existing structure that's similar to generate an approximate set of phases (information which you cannot gain from the diffraction pattern), but also by locating heavy (or anomalously dispersing) atoms in the unit cell (exactly like small molecule crystallography)).
Having solved the structure, you then need to refine it. You'll typically have 1000-4000 heavy (non-H) atoms in the single protein molecule, so the positions, temperature factors and occupancies of these atoms need to be refined - the product of which is your 'X-ray crystal structure', which is in fact a model based on the data you collected.
Because the data you collected probably comprises something like 10,000 to 30,000 unique data points, and you have, say 2000 atoms, each with x, y and z coordinates (that's 6000 parameters), and some contribution from temperature factor estimation, and probably a further 20-400 water molecules (depending on resolution), each of which has another 4 parameters associated (assuming an occupancy of 1 for each), your observation to parameter ratio gets quite small (approaching 1 is bad!).
Protein crystals which diffract more strongly and give measurable diffracted X-ray spots at around, say, 1.5 Angstrom resolution tend to give much more reliable models, but even these require a LOT of approximations. We are helped enormously by the requirements of chemical bonding, of course: peptide bonds tend to be planar, due to the lone pair of electrons on amide nitrogen atoms being partially delocalised with the formal pi orbitals of the adjacent carbonyl group; bond angles and bond distances tend to be pretty well defined; there are fairly few rotamers (conformations of amino acid side-chains) which are much more likely than others (again, due to chemical bonding restraints); certain values of phi and psi (and omega) - the angles within and between adjacent peptide bonds - are much more likely than others, and define the secondary structural elements, such as alpha helices, beta sheets, strict beta turns, eta helices and so on. All of these restraints, which we know largely from small molecule crystallography, help to reduce the apparent observation to parameter ratio by restricting the values that some of our parameters can take (eg by limiting in space (x,y and z) where a certain atom can be based on its bonding pattern with neighbouring atoms).


Oops, looks like I got a bit carried away and re-derailed this topic again...

Roo

How do you get the baseline models to extrapolate from? It strikes me that a computational technique like DPD, or straight up atomistic modelling would be usefull to create some starting points? 1.5 angstroms is a tad clumsy - can you get atomistic resloution reliably out of that? Seems that its very much the broad strokes of the molecular structure, how do you fill in the fine detail? The statistical interpolation at the end worries me...

1.5 Angstroms is actually very good resolution for X-ray crystal structures of protein. You can see alpha helices at around 6 Angstroms, amino acid side chains at around 3.5-4 Angstroms, ring pucker on 5-rings of proline at about 2.4 Angstroms, holes through phenylalanine, tyrosines and tryptophans at about 1.6-1.9 Angstroms, holes through histidines at around 1.5 Angstroms, bulges where hydrogens go at around 1.2 Angstroms or so. Full 'atomic' resolution for proteins at any rate would be typically better than 1 Angstrom. But, considering the bonding requirements, you'll find extremely high confidence in atomic positions even at 2.5 Angstrom resolution data.
In any case, the initial model for molecular replacement will typically be another protein structure (less waters and any bound ligands), and the current dataset is usually trimmed at about 2.5 to 3.5 Angstroms (ie using the low resolution data only) for correct positioning of the starting model. Once this is in place, you can calculate approximate phases for each reflection and compare the model with the experimental data.

Be under no illusions: as inexact as this may seem, the results are surprisingly accurate. I would contest anyone who builds this structure with any atoms even 0.05 Angstroms from their current positions (the blue stuff is a representation of electron density weighted towards the experimentally observed values, the resolution is 1.55 Angstroms):